PHYS-E0551 Homework assignment 5: Superconductivity (due Oct 15) Homework assignment 5: Superconductivity (due Oct 15) 1. At T = 0, find the minimum voltage V = µL − µR above which quasiparticle can flow for a) NSN, b) SNS, and c) SSS superconducting tunnel structures. Consider gate charge ng = 0 so that the island charge states involved are n = 0 and n = 1. Current can flow if both transition rates ΓL→I (n) and ΓI→R (n + 1) are finite. Remember the charging energy of the center island I. 2. Consider a superconductor carrying supercurrent. Take ∆(r) = |∆|eiq·r with constant |∆|. q is the momentum of the superflow. (a) Find the quasiparticle energy spectrum k from the Bogoliubov de Gennes equation: ! ~2 ∇2 − µ ∆(r) − 2m u(r) u(r) = ~2 v(r) v(r) ∆(r)∗ −[− 2m ∇2 − µ] (1) Try Ansatz uk (r) = Uk ei(k+q/2)·r , vk (r) = Vk ei(k−q/2)·r . You can simplify things by assuming |q| |k| so that |k + q|2 ≈ |k|2 + 2k · q. (For each k there are two eigenenergies k,+ and k,− , since it’s a 2 × 2 matrix. For q = 0, k,+ > 0 and k,− < 0. k,+ are the excitation energies.) (b) Determine the critical superflow velocity vs,c = ~|q| 2m above which for some k, k,+ < 0. q Since |q| |k|, it’s enough to check the condition only at wavevectors k = ±kF |q| , where kF = p 2mµ/~2 is the Fermi wavevector. (c) If some excitation energies are negative, k,+ < 0, is the BCS vacuum ground state still the state with the lowest energy? What will happen experimentally when the superflow is too large? (d) The charge current density is jc = ens vs , where ns is superconducting electron density. Estimate the order of magnitude of maximum supercurrent density (= critical current density) in aluminum. At T = 0 for aluminum, ns ≈ n = free electron density ∼ 1029 m−3 , and |∆| ∼ 200 µeV. For 3D metals, kF = (3π 2 n)1/3 . What is the critical current of an aluminum microstrip with cross-section 1 µm × 100 nm? ~ 3. Estimate the average voltage V¯ = 2e ∂t ϕ across a Josephson junction (overdamped) at |I| Ic caused by thermal fluctuations. Assume the dynamics of the junction in this regime is described by motion of ~ ϕ in the “washboard” potential U (ϕ) = −EJ cos(ϕ) − 2e Iϕ, with EJ = ~Ic /(2e). (a) Thermal activation follows Arrhenius law: rate Γ± = ω0 e−U± /(kB T ) . Determine the barriers U± for transitions between neighboring washboard potential minima (ϕ 7→ ϕ ± 2π). Simplify by assuming I Ic so the minima are at ≈ 0, ±2π, ±4π, . . .. (b) Evaluate the average voltage based on the estimated transition rates. (c) Estimate ω0 by requiring that at kB T ≈ EJ , dV dI |I=0 is equal to the normal-state resistance RN . (d) Sketch the resulting current-voltage relation. (updated 2014-10-03 17:31:25)
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