数学Ⅰ レポート No.5 1. つぎの二重積分を計算せよ. 1 1 (1) (2) dy (3) dy ( x 2 y 3 2 x 3 y 2 )dx 0 0 1 1 0 0 dy 2 cos( x 2 y )dx 2 0 1 0 (4) (5) dy 0 1 dx (1 x)(1 2 y ) dy xy 3 dx 0 1 2x 2 y 2 1 1 1 0 0 y log(1 2 xy )dx 2. つぎの三重積分を計算せよ. (1) (2) 1 0 1 1 0 0 dz dy ( x 3 y 3 z 3 3xyz )dx 4 0 4 0 0 dz dy 4 sin( x y z )dx x2 2y2 z2 dx 1 1 1 xyz 1 1 1 1 (4) dz dy dx 0 0 01 x 2y z (3) (5) 2 dz dy 2 2 1 dz dy 1 1 0 0 0 x 2 y z dx 2016
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