Math 559 MODERN GEOMETRY SOLUTION FOR QUIZ – I (09/11) September 18 (Thu), 2014 Instructor: Yasuyuki Kachi Line #: 13191. [I] (4pts) (1) Homogenization of ◦ Alternatively, (2) ◦ Alternatively, (1) with respect to Z is (2) y, z X : Y : Z = X : Y = Homogenization of [II] (4pts) ′ x, z : Z ′ X : Y : Z = X : Y = : Z De-homogenization of −3 8 1 : 1 8 : 1 5 −3 . 8 is 5 : 10 : 2 . 1 2 : 1 : 1 . 5 X : Y : Z = −1 : 1 : 4 Homogenization of = with respect to Y is not feasible. [III] (2pts) is 8 : 1 : −3 . −1 1 . , 4 4 X : Y : Z = 1 : 0 : 3 x′′ , y ′′ De-homogenization of 1 , = 8 1 = , 2 11 ′ x + 4 5 ′ z + 1 = 0 4 11 X + 4 Y + 5 Z = 0. 1 is [IV] (6pts) (1) De-homogenization of X − Y + Z = 0 with respect to Y is x′ + z ′ − 1 = 0. (2) De-homogenization of X − Y = 0 with respect to Z is x′′ − y ′′ = 0. [V] (3pts) Suppose y, z = √ 2, 1 is the coordinate reading of a point of UX using the affine coordinate of UX . Then the coordinate reading of the same point using the affine coordinate of UZ is √ x′′ , y ′′ = 1, 2 . [VI] (5pts) UY The conversion formula to express the affine coordinate in terms of the affine coordinate y, z of UX : x′ = [VII] (6pts) (1) Suppose 1 , y z′ = x′ , z ′ of z . y − 5 x′ + 7 z ′ + 12 = 0 is the equation of a line in UY using the affine coordinate of UY . Then the equation of the same line using the affine coordinate of UZ is − 5 x′′ + 12 y ′′ + 7 = 0. (2) Suppose y = 0 is the equation of a line in UX using the affine coordinate of UX . Then there is no equation of the same line using the affine coordinate of UY . The line is outside of UY . 2
© Copyright 2024 ExpyDoc