Trigonometry Unit 5 Packet Name_____________________ Hr___ Mathematical Identities An identity is an equation that is true for ALL possible values of the value for which the equation is defined. EXAMPLE: Most equations are not identities because an equation is not necessarily true for all values of the variables involved. Circle the equations that are IDENTITIES: 2 x x2 x 13 x2 y 2 x y x 6 x3 x 7 2 x 2 49 x 5 x 5 x2 25 x2 x The most commonly used identities in Trigonometry are the Pythagorean identities. Why do you think they are called by that name? 1. Use the Pythagorean Thm to write an equation that relates x, y, and r. 2. What ratio is equal to ? 3. What ratio is equal to ? 4. Using substitution and simplification, combine the three equations above to write a single equation in terms of θ. Since the identity should be true for ALL values, let’s explore angles in all four quadrants: QI QII QIII QIV Trigonometry Unit 5 Packet Trigonometry Triangles Directions: Place the names of the six trigonometric functions in the order which we learned them ( at the vertices labeled A, B, C, D, E, and F respectively. Shade or color in the triangle with vertices A, B, and the center. Then shade in the triangle whose vertices are at D, F, and the center, and the triangle whose vertices are at C, E, and the center. Reciprocal Identities: The Pythagorean Identities: For Product Identities: Along the two trigonometric functions each shaded triangle, the upper- outside edge of the hexagon, any on any diagonal are left function squared plus the trigonometric function equals the reciprocals of each other. upper-right function squared product of the functions on the equals the bottom function adjacent vertices. squared. Trigonometry Unit 5 Packet Verifying Identities1 Hints for verifying identities: 1. If one side of an equation looks more complex, start there. EXAMPLE: tan 2 x(1 cot 2 x) 1 1 sin 2 x 2. Try changing everything into sin/cos. EXAMPLE: cot x 1 csc x cos x sin x 1 WARNING: Do NOT handle the identities to be established as equations. You cannot add the same expression to both sides, etc. Trigonometry Unit 5 Packet 3. Factor. Example: sec4 x sec2 x tan 4 x tan 2 x 4. Create a common denominator. EXAMPLE: 1 1 2sec2 x 1 sin x 1 sin x Trigonometry Unit 5 Packet Sum and Difference Identities tan( A B) tan A tan B 1 tan A tan B tan( A B) tan A tan B 1 tan A tan B EXAMPLE 1: Find the exact value of each expression. a) b) c) d) ( ) e) f) EXAMPLE 2: Suppose that and both and are in quadrant II. Find Trigonometry Unit 5 Packet Double-Angle Identities EXAMPLE 1: Given sin 2 (QIII) find: 3 cos 2 sin 2 EXAMPLE 2: Given that sin EXAMPLE 3: Simplify EXAMPLE 4: Simplify 2 tan 2 and cos 0 , find tan 2 . 5 3 . 1 tan 2 3 . tan 2 Trigonometry Unit 5 Packet Half-Angle Identities √ √ √ EXAMPLE 1: Find the exact value of: a) EXAMPLE 2: Given b) , with , find: a) b) EXAMPLE 3: Simplify: 1 cos12 x 2 EXAMPLE 4: Evaluate tan 9 . 8 EXAMPLE 5: Let csc 5 (QIII). Find tan 2 . Trigonometry Unit 5 Packet PRACTICE: Match the term in column I with the term in column II that completes the identity. Answer I 1. cos x sin x A. 2. B. 3. C. 4. D. 1 sec 2 x 5. E. 6. – sin 2 x F. cos 2 x sin x G. cos x 7. 8. sec x csc x H. 9. I. 10. J. 11. Suppose a student writes, “ 12. Another student claims, “Since both sides to get II ” What is wrong with this statement? , you can take the square root of .” TRUE or FALSE? Explain. Trigonometry Unit 5 Packet Find the EXACT value: 13. cos165 15. sin105 14. cos 16. 17. tan 20 tan 25 1 tan 20 tan 25 18. tan 19. 2 tan15 . 1 tan 2 15 20. 21. 2cos2 15 1 23. cos 22.5 7 12 7 12 tan 34 . 2 1 tan 2 34 22. cos 7 8 24. tan 22.5 Trigonometry 25. sin Unit 5 Packet 3 8 26. 27. Let sin 1 cos 59.74 sin 59.74 4 1 (QIV) and cos (QI). Find cos 5 5 28. Suppose that A and B are angles in standard position, with , and . Find each of the following: a) b) c) the quadrant of SIMPLIFY the expressions: 29. 31. 30. 1 cos 5 sin 5 1 cos8 1 cos8 32. Let sin 1 (QIV). Find cos 2 . 3 33. Let cos 3 (QI). Find sin 2 . 5 Trigonometry Unit 5 Packet 34. Given that cos find tan 2 . 3 and sin 0 , 5 36. Let sec 2 (QIV). Find: sin cos 2 37. Let sin sin 5 and 7 cos 0 , find cos 2 . 35. Given that sin tan 2 2 1 (QIV). Find: 3 cos 2 2 38. Is this problem solved correctly? If not, correct the error(s): Problem: Solve . tan 2 Trigonometry Unit 5 Packet EXPANSION 1: Using the information in the picture below, write an expression to represent tan 4 . b 50 50 EXPANSION 2: Prove that cos cos 2cos cos . EXPANSION 3: Given that cos 12 1 4 6 2 , evaluate cos 24 . EXPANSION 4: Use the fact that tan 3x tan 2 x x to establish an identity for tan 3x . EXPANSION 5: Show that the area A of an isosceles triangle whose equal sides are of length s and the angle between them is θ is: A 1 2 s sin . 2 s θ s
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