Introduction to the Smith Chart

Smith-Chart
Smith-Chart
Division of Electrical- and Communication Engineering
Engineering and Information Technology
Berne University of Applied Sciences
Introduction
to the
School of
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
From theory of lines:
Z
−1
Z − Z0 Z0
Γ=
=
Z
Z + Z0
+1
Z0
Eq. 1
Γ : complex Reflection Coefficient = Γ ∠θ
Z : complex Impedance = R + jX
Z0 : Normalizing Impedance (usually real)
Smith Chart
Normalized Z = z
Prof. F. Dellsperger
1
2
NT2
z=
Z
R
X
=
+j
= r + jx
Z0 Z0
Z0
Eq. 2
Γ=
z − 1 r + jx − 1
=
z + 1 r + jx + 1
Eq. 3
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=0
.8
45
Γ
Γ =1
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Γ = 0.8∠60o
135
Berne University of Applied Sciences
90
School of
Γ = Γ ∠θ
Division of Electrical- and Communication Engineering
Smith-Chart
Representation of Reflection Coefficient in Polar Diagram:
Division of Electrical- and Communication Engineering
According to Eq.1, each reflection coefficient must also represent a
complex impedance Z, or according to Eq.3 a complex normalized
impedance z.
For Γ = 0.8∠60o and Z0 = 50Ω from Eq.1 and 3:
90
1+ Γ
1 + 0.8∠60o
Z = Z0
= 50Ω
1− Γ
1 − 0.8∠60o
= (21.429 + j82.479)Ω
Γ = 0.8∠60o
135
0.6
0.8
1 + Γ 1 + 0.8∠60o
=
1 − Γ 1 − 0.8∠60o
= 0.429 + j1.65
z=
1 0
θ
θ=
0.4
Γ
o
60
0.2
o
60
±180
45
.8
θ=
θ
Γ = 0.8∠60o
Z = (21.429 + j82.479)Ω
z = 0.429 + j1.65
=0
Engineering and Information Technology
School of
Berne University of Applied Sciences
Smith-Chart
0.2
±180
0.4
0.6
0.8
1 0
0≤ Γ ≤1
225
-135
3
315
-45
270
-90
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225
-135
4
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315
-45
270
-90
1
Smith-Chart
Engineering and Information Technology
School of
This would help to visualize Eq. 1 and 3.
It would also help to visualize the effect of changing
elements in a network.
Division of Electrical- and Communication Engineering
Let‘s first consider a few special points.
Why not overlay a grid with impedance values?
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
Smith-Chart
For example:
In a given load impedance consisting of a serie R – L
network the value of L changes by a certain value.
How does it affect the reflection coefficient (or VSWR)?
Short circuit: R=0, X=0, (r=0, x=0)
Γ=
−1
= −1 = 1∠180o
1
90
Open circuit: R=∞, X=0, (r=∞, x=0)
135
Γ = 1 = 1∠0o
45
Z=Z0: R=50, X=0, (r=1, x=0)
Γ=0
0.2
±180
Short
0.4
0.6
6
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315
-45
270
-90
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Smith-Chart
Smith-Chart
r= 1
±180
1
0.2
0.4
0.6
0.8
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45
School of
135
7
r + jx − 1 −0.5 + jx
=
r + jx + 1 1.5 + jx
135
45
r = 0.5
±180
0.5
1
0.2
0.4
0.6
0.8
1 0
-0.1
-0.5
-1
-2
-4
-10
+1
+0.1
+∞
+10
+4
+2
0
-∞
x = +0.5
225
-135
This gives a
constant-r-circle
for r=0.5
315
-45
270
-90
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90
Γ=
1 0
-0.1
-0.5
-1
-2
-4
-10
+1
+0.1
+∞
+10
+4
+2
0
-∞
x = +0.5
This gives a
constant-r-circle
for r=1
Division of Electrical- and Communication Engineering
Draw the locus for r=0.5 (R=0.5Z0) and -∞<x<+∞
90
r + jx − 1
jx
=
r + jx + 1 2 + jx
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
Draw the locus for r=1 (R=Z0) and -∞<x<+∞
Γ=
1 0
Open
225
-135
5
0.8
Z0
8
225
-135
315
-45
270
-90
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2
Smith-Chart
Smith-Chart
2
4
r = 0.2
±180
0.2
0.5
1
0.2
0.4
2
0.6
4
0.8
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45
School of
135
Division of Electrical- and Communication Engineering
Locus for r=0.2, 0.5, 1, 2, 4 and -∞<x<+∞
90
r + jx − 1
Γ=
r + jx + 1
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
Draw the locus for r=0.2, 2, 4 and -∞<x<+∞
90
Γ=
r + jx − 1
r + jx + 1
45
r = 0.2, 0.5, 1, 2, 4
-∞<x<+∞
1 0
135
180
0.2
0.5
1
0.2
0.4
2
0.6
4
0.8
1 0
-0.1
-0.5
-1
-2
-4
-10
+1
+0.1
+∞
+10
+4
+2
0
-∞
x = +0.5
Locus for constant
real part of impedance
More
225
-135
315
-45
225
-135
315
-45
constant-r-circles
270
-90
9
270
-90
10
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Smith-Chart
Smith-Chart
45
0.2
2
x= 1
±180
0.2
0.5
1
0.2
0.4
2
0.6
4
0.8
Engineering and Information Technology
135
School of
1
Division of Electrical- and Communication Engineering
Draw the locus for x=-1 (X=-Z0) and 0<r<+∞
90
r + jx − 1 r + j1 − 1
Γ=
=
r + jx + 1 r + j1 + 1
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
Draw the locus for x=1 (X=Z0) and 0<r<+∞
90
Γ=
r + jx − 1 r − j1 − 1
=
r + jx + 1 r − j1 + 1
1
135
0.2
2
x = -1
1 0
±180
1
4
+∞
0
0
20.2
r = 0.5
45
0.2
0.5
1
0.2
0.4
2
0.6
4
0.8
1 0
1
4
+∞
0
0
20.2
r = 0.5
225
-135
315
-45
225
-135
315
-45
-1
11
270
-90
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12
270
-90
NT2
3
Smith-Chart
Smith-Chart
Impedance plane
0.2
4
-10
-4
-2
+0.2
-0.5
+2
+10
+0.5
+4
x = -0.2
0.5
1
0.4
0.6
2
0.8
4
1 0
0
r = 0<r<+∞
4
0.2
0.5
2
1
-4
225
-135
-2
-0.5
315
-45
-2
-0.5
-1
270
-90
-1
270
-90
14
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Smith-Chart
Impedance plane
±180
0
Zin 0.2
0.5
2
1
Zin
L/Z
0
225
-135
-0.5
Z1
jx=-jZ0/ωC
Zin
-2
1
135
Zin
R
0.5
2
4
r=R
/Z
NT2
0
Zin
Z1
±180
0
0.2
0.5
2
1
0
4
∞
Zin
r=
Z1 = R1 + jX1
Zin = (R1 + R ) + jX1
315
-45
-0.2
225
-135
0
R/Z
-4
Z1
-2
-0.5
-1
Real part of impedance = constant
45
0.2
Z1
∞
-4
90
Serie R
0
4
-0.2
jx=
jω
School of
4
Berne University of Applied Sciences
Z1
Zin = R + j(X1 ± X)
+jx (inductive)
Z1
0.2
Z1 = R1 + jX1
45
-jx (capacitive)
jx=
jω
L/Z
jX
2
0
0.5
135
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1
Zin
Division of Electrical- and Communication Engineering
90
Serie L or C
jx=-jZ /ωC
0
Division of Electrical- and Communication Engineering
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Berne University of Applied Sciences
Impedance plane
315
-45
+jx (inductive)
225
-135
Smith-Chart
15
∞
-0.2
Locus for constant
imaginary part of
impedance
Zin
0
4
-4
-0.2
13
45
-jx (capacitive)
0.2
0.2
2
0.2
±180
±180
0.5
+jx (inductive)
45
1
135
-jx (capacitive)
2
Engineering and Information Technology
0.5
135
School of
1
Division of Electrical- and Communication Engineering
90
r + jx − 1
Γ=
r + jx + 1
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
Draw the locus for x=±0.2, ±0.5, ±2, ±4, ±10 and 0<r<+∞
90
315
-45
-1
270
-90
Imaginary part of impedance = constant
16
270
-90
NT2
4
Smith-Chart
l
Z1
1− Γ
|Γ|
=
=
2
0.6
The center of constant
VSWR-circle is the center
of Smith-Chart if SmithChart is normalized to the
line impedance.
18
NT2
-0.2
225
-135
0.5
VS
W
R
=
Division of Electrical- and Communication Engineering
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Y : complex Admittance = G + jB
-4
-2
-0.5
270
-90
.8
=0
Γ
1 − Γ 1 − 0.8∠60o
=
1 + Γ 1 + 0.8∠60o
= 0.163 − j0.675
y=
0.2
±180
225
-135
20
NT2
θ
o
Eq. 6
45
60
NT2
1 − y 1 − g − jb
=
1 + y 1 + g + jb
Γ = 0.8∠60o
135
Γ = 0.8∠60o
Y = (3.253 − j13.5)mS
y = 0.163 − j0.675
θ=
19
Γ=
315
-45
-1
90
1− Γ
1 − 0.8∠60o
= 20mS
Y = Y0
1+ Γ
1 + 0.8∠60o
= (3.253 − j13.5)mS
Normalized Y = y
Eq. 5
0
8
4
For Γ = 0.8∠60o and Z0 = 50Ω from Eq.1 and 3:
Y0 = 1/ Z0
Y
G
B
=
+j
= g + jb
Y0 Y0
Y0
1
According to Eq.4, each reflection coefficient must also represent a
complex admittance Y, or according to Eq.6 a complex normalized
admittance y.
Y0 : Normalizing Admittance (usually real)
y=
0.8
4
Smith-Chart
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
Γ : complex Reflection Coefficient = Γ ∠θ
0.6
2
NT2
Admittance Chart:
Eq. 4
4
0.4
1
Smith-Chart
Y
1−
Y0 − Y
Y0
Γ=
=
Y0 + Y 1 + Y
Y0
45
Zin
Z1
0.2
Load
R
2
0.2
0
d
towar
Load
17
d
towar
VSWR =
1+ Γ
-jx (capacitive)
± 180
VS
W
0.2
Gener
l
Z = Z0
0.5
+jx (inductive)
ator
Zin
1
135
-jx (capacitive)
with ZL = Z0
90
towar
d
Division of Electrical- and Communication Engineering
Gener
ator
+jx (inductive)
constant |Γ| and VSWR
Engineering and Information Technology
Serie Transmission line
School of
Circles of
Berne University of Applied Sciences
Impedance plane
towar
d
Division of Electrical- and Communication Engineering
Engineering and Information Technology
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Berne University of Applied Sciences
Smith-Chart
Impedance plane
0.4
0.6
0.8
1 0
315
-45
270
-90
5
-0.2
Division of Electrical- and Communication Engineering
-4
Engineering and Information Technology
-0.4
-2
School of
-1
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
Locus for constant
imaginary part of
admittance
Admittance plane
Admittance plane
-1
Parallel L or C
∞
4
0.4
1
2
0.2
21
/ω
L
Y1
-4
jB
Y1
4
2
1
0.4
-0.2
0.2
0
Yin
4
Yin
Yin = G + j(B1 ± B)
0.2
jb
2
Real part of admittance = constant
0.4
22
1
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jY
0
4
2
-0.4
jb
=-
0
Yin
Y1 = G1 + jB1
Locus for constant
real part of admittance
Yin
-2
∞
School of
Using the similar procedure as
with the impedance plane we
get circles for constant
conductance g and arcs for
constant susceptance b.
Smith-Chart
/Y
jb=jωC 0
Berne University of Applied Sciences
Smith-Chart
Yin
jb=jωC/Y 0
Y1
jY
=-
/ω
0.2
L
0
0.4
1
NT2
Smith-Chart
Smith-Chart
90
±180
Constant Q circles
-0.24
-40.2
4
0.2
0
0.4
1
2
1
0.4
0.2
4
2
4-0.2
225
-135
NT2
0
0.2-4
2
0.4
-0.4
1
23
45
-2
315
-45
Division of Electrical- and Communication Engineering
2
Engineering and Information Technology
-0.4
School of
1
Berne University of Applied Sciences
-2
+jx, -jb (inductive)
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Overlay of
impedance and
admittance plane
∞
Berne University of Applied Sciences
135
0.4
Q=
X G
= = cons tan t
R B
0
∞
-jx, +jb (capacitive)
-1
Imittance Chart
-1
270
-90
24
NT2
6
27
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28
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
www.hta-be.bfh.ch/~dellsper
Division of Electrical- and Communication Engineering
NT2
Engineering and Information Technology
DP-Nr. 1
DP-Nr. 2
DP-Nr. 3
DP-Nr. 4
DP-Nr. 5
DP-Nr. 6
School of
25
Berne University of Applied Sciences
Division of Electrical- and Communication Engineering
Engineering and Information Technology
School of
Berne University of Applied Sciences
Smith-Chart
Smith-Chart
Example using „Smith“-Software
L-networks for maching Z2 to Z0
(7.7 - j7.4)Ohm Q = 1.0 470.000 MHz
(14.8 + j0.0)Ohm Q = 0.0 470.000 MHz
(14.8 - j14.3)Ohm Q = 1.0 470.000 MHz
(28.6 + j0.2)Ohm Q = 0.0 470.000 MHz
(28.6 + j24.4)Ohm Q = 0.9 470.000 MHz
(49.5 + j0.0)Ohm Q = 0.0 470.000 MHz
26
NT2
Smith-Chart
Smith-Chart
L-networks for maching Z2 to Z0
„Smith“-Software
www.fritz.dellsperger.net
NT2
7