AMATH 383 Winter 2014 Homework 5 Due: Thursday, February 13, 2014 Show work for full credit! 1. Harvesting problem Obtain, by hand, the explicit solution to the harvesting problem N dN = rN 1 − − H(N ), H = qEN dt K subject to the initial condition N (0) = N0 . Here N = N (t). The parameters r, K, q, and E are positive constants. Deduce the two limiting behaviors as t → ∞. 2. Fish population For a fish population modeled by a depensation growth model, we have, when there is harvesting, dN = F (N ) − H(N ) dt where N N F (N ) = rN −1 1− NC K and H(N ) = qEN . (a) Find and plot, freehand, the sustained (nontrivial stable) yield H(N3∗ ), the unsustainable (unstable) yield H(N2∗ ), and the trivial stable yield H(N1∗ ) as a function of effort E on the same figure. (b) Find the E(= Emax ), where the two curves in (a) merge (this happens when N2∗ = N3∗ ). What happens to the fishery and the fish population when E = Emax ? (c) What happens if harvesting is done at an effort level E > Emax ? What will happen if, after the effort level was raised above Emax , it is then lowered below Emax again? 1 3. Mouse population cycles It has been observed that plagues appear in mice populations whenever the population becomes too large. Further, a local increase of density attracts predators in large numbers. These two factors will succeed in destroying 97-98% of a population of small rodents in two or three weeks, and the density then falls to a level at which the disease cannot spread. The population, reduced to 2% of its maximum, finds its refuges from the predators sufficient, and its food abundant. The population therefore begins to grow again until it reaches a level favorable to another wave of disease and predation. Assume the following: During “Phase 1,” the growth phase, the population grows from the minimum value q until it reaches the maximum value Q according to N 0 = aN. During “Phase 2,” the epidemic phase, and the population shrinks from the maximum value Q until it reaches the minimum value q according to N 0 = −BN 2 . After the population shrinks to q, it enters Phase 1 and the cycle begins again. (a) Show that time spent in Phase 1, T1 , and time spent in Phase 2, T2 , are given by Q Q−q 1 , T2 = . T1 = ln a q qQB (b) Given T1 = 4 years, T2 = 2 weeks, Q = 100, and q = 2, determine values for a and B. (c) Sketch or plot the population over one period of the cycle: T1 + T2 , using the values from (b). (d) Describe your results from parts (b) and (c) in terms of the system being modeled. 2 4. Smallpox In 1760 Daniel Bernoulli developed a model for the spread of smallpox, which at the time was a major threat to public health. His goal was to determine whether or not a controversial inoculation program would be effective. His model applies equally well to any disease where survival after contraction of the disease results in lifelong immunity. Consider the cohort of individuals born in a given year (ie: at time t = 0). Let n(t) be the total number of these individuals who are still alive t years later. Let x(t) be the number of members of the cohort who have not contracted smallpox by year t, and are therefore still susceptible. Let β be the rate at which susceptibles contract smallpox, and let ν the chance that people who contract smallpox die from the disease. Finally, let µ(t) be the death rate from all causes other than smallpox. Then the population is governed by the following differential equations: dx = − (β + µ(t)) x dt dn = −νβx − µ(t)n dt (a) Explain why these equations govern the population described above. (b) Let z = x n and show that z satisfies the initial value problem dz = −βz (1 − νz) , dt z(0) = 1. (c) Describe what z represents in terms of the population being modeled. (d) Solve this new equation for z(t). (Hint: The equation now resembles the differential equation for the logisitic model. You may cite the formula for the solution to the logistic model from the lecture notes.) (e) Bernoulli estimated that ν ≈ 81 yr−1 and β ≈ 18 . Using these values, sketch or plot z(t), describe your plot, and determine the proportion of 20-year-olds who have not had smallpox. Note: Based on the model described above and using the best mortality data available at the time, Bernoulli calculated that if deaths due to smallpox could be eliminated (if you could somehow make ν = 0), then approximately 3 years could be added to the average life expectancy in 1760: 26 years and 7 months. Therefore Bernoulli supported the proposed inoculation program. 3
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