➨3❶ 1UPᩘᏛ ᑐᩘ䠄log䠅䛾⩦ ܽ = ݔ௬ • ܽ䜢ఱ䛧䛯䜙ݔ䛻䛺䜛䛛䜢▱䜚䛯䛔䚹 • ⯆䛾ᑐ㇟䛿ݕ䛾್䚹 • 䛣䛾䛸䛝䚸 = ݕlog ݔ䛸䛧䛶ồ䜑䜛䛣䛸䛜䛷䛝䜛䚹 ⤫ィᏛ䛷䜘䛟⏝䛔䜛 4䛴䛾ᇶᮏᛶ㉁䛾䛚䛥䜙䛔 2015.11.04 ᑿᓮᖾㅬ䞉Ⲯᓥᏹ㑻 ᇶᮏ1 log ܽ = 1 ᗏ䛸┿ᩘ䛜➼䛧䛔䛸1 㢟 2 = 2௬ 3 = 3௬ 4 = 4௬ 5 = 5௬ ព ⟅䛘 ᑐᩘ 2䜢ఱ䛧䛯䜙2䛻䛺䜛䛛 1 = ݕlog ଶ 2 = 1 3䜢ఱ䛧䛯䜙3䛻䛺䜛䛛 1 = ݕlog ଷ 3 = 1 4䜢ఱ䛧䛯䜙4䛻䛺䜛䛛 1 = ݕlog ସ 4 = 1 5䜢ఱ䛧䛯䜙5䛻䛺䜛䛛 1 = ݕlog ହ 5 = 1 ᇶᮏ2 log 1 = 0 ┿ᩘ䛜1䛾䛸䛝䛿0 㢟 1 = 2௬ 1 = 3௬ 1 = 4௬ 1 = 5௬ ព ⟅䛘 ᑐᩘ 2䜢ఱ䛧䛯䜙1䛻䛺䜛䛛 0 = ݕlog ଶ 1 = 0 3䜢ఱ䛧䛯䜙1䛻䛺䜛䛛 0 = ݕlog ଷ 1 = 0 4䜢ఱ䛧䛯䜙1䛻䛺䜛䛛 0 = ݕlog ସ 1 = 0 5䜢ఱ䛧䛯䜙1䛻䛺䜛䛛 0 = ݕlog ହ 1 = 0 = ݕlog ݔ ┿ᩘ ᗏ䠄䛶䛔䠅 • ݕ䜢ܽ䜢ᗏ䠄䛶䛔䠅䛸䛩䜛┿ᩘݔ䛾ᑐᩘ䛸䛔䛖䚹 • ܽ = ݁ 䠄䝛䜲䝢䜰ᩘ䠅䛾䛸䛝䚸 = ݕlog ݔ䛺䛹䛸䛧䜀䛧䜀␎グ ᇶᮏ3 log ܾ = ܿ × log ܾ 㢟1 ゎㄝ 㢟2 ゎㄝ 㢟3 ゎㄝ 㢟4 ゎㄝ 8 = 2௬ 2䜢ఱ䛧䛯䜙8䛻䛺䜛䛛䠄3䠅 = ݕlog ଶ 8 = log ଶ 2ଷ = 3 × log ଶ 2 = 3 9 = 3௬ 3䜢ఱ䛧䛯䜙9䛻䛺䜛䛛䠄2䠅 = ݕlog ଷ 9 = log ଷ 3ଶ = 2 × log ଷ 3 = 2 27 = 3௬ 3䜢ఱ䛧䛯䜙27䛻䛺䜛䛛䠄3䠅 = ݕlog ଷ 27 = log ଷ 3ଷ = 3 × log ଷ 3 = 3 625 = 5௬ 5䜢ఱ䛧䛯䜙625䛻䛺䜛䛛䠄4䠅 = ݕlog ହ 625 = log ହ 5ସ = 4 × log ହ 5 = 4 㢟5 0.01 = 0.1௬ 0.01䜢ఱ䛧䛯䜙0.1䛻䛺䜛䛛䠄2䠅 ゎㄝ = ݕlog .ଵ 0.01 = log .ଵ 0.1ଶ = 2 × log .ଵ 0.1 = 2 ᇶᮏ4 log ܾܿ = log ܾ + log ܿ 㢟1 ゎㄝ 㢟2 ゎㄝ 4 = 2௬ 2䜢ఱ䛧䛯䜙4䛻䛺䜛䛛䠄2䠅 = ݕlog ଶ 4 = log ଶ (2 × 2) = log ଶ 2 + log ଶ 2 =2 27 = 3௬ 3䜢ఱ䛧䛯䜙9䛻䛺䜛䛛䠄3䠅 = ݕlog ଷ 27 = log ଷ (3 × 9) = log ଷ 3 + log ଷ 9 = 1 + log ଷ (3 × 3) = 1 + log ଷ 3 + log ଷ 3 =3
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