Homework 3 Problems β Heat Engines and the 2nd Law 1. The idealized Otto cycle is given below a. Show that the efficiency of the Otto cycle can be written solely in terms of the compression ratio π = π1 /π2 as πβ = 1 β π1βπΎ Do you think that the efficiency of the cycle depends only on the compression ratio when other effects such as friction are taken into account? Would expect a real engine to be most efficient when operating at high power or at low power? Defend your answer. b. Show that the efficiency of the Otto cycle is less than a corresponding Carnot cycle acting between the highest and lowest temperatures. c. Suppose that the compression ratio of the above Otto cycle is π = 8.00. At the beginning of the compression process, 500 cm3 of gas is at 100 kPa and 20.0β°C. At the beginning of the power stroke, the temperature is 750β°C. Modeling the working substance as a diatomic ideal gas, determine the energy input, energy exhaust, and net work of the cycle. 2. A reversible heat engine operates between two reservoirs, ππΆ = 250 πΎ and ππ» = 400 πΎ. The cold reservoir can be considered to have infinite mass, but the hot reservoir consists of a finite amount of gas at constant volume (1 mole with a specific heat ππ = 3200π½/ππ β). As a result, the temperature of the hot reservoir decreases with time, and after the heat engine has operated for some long period of time, the temperature ππ» is lowered to ππΆ . Calculate the heat extracted from the hot reservoir during this period and the amount of work performed by the engine during this period. 3. The idealized Diesel cycle is given below a. Show that efficiency of the Diesel cycle can be written in terms of the compression ratio π = ππ΄ /ππ΅ and the cut-off ratio π = ππΆ /ππ΅ as π1βπΎ (π πΎ β 1) πβ = 1 β πΎ(π β 1) b. Show that for a given compression ratio, the Diesel cycle is less efficient than the Otto cycle. c. In a Diesel engine, atmospheric air is quickly compressed to about 1/20 of its original volume. Estimate the temperature of the air after compression, and explain why a Diesel engine does not require spark plugs. 4. One mole of a monotonic ideal gas is carried through the Carnot cycle described below. At point π΄, the pressure is 25.0 atm and the temperature is 600 K. At point C, the pressure is 1.00 atm and the temperature is 400 K. a. Determine the pressures and volumes at points A, B, C, and D. b. Calculate the net work done per cycle. c. Determine the efficiency of an engine operating in this cycle. 5. In this question, you will analyze the thermodynamics of the Stirling heat engine. a. Based on the description of the Stirling heat engine in class, draw a PV diagram for this idealized Stirling cycle. Label each step in the engineβs cycle. b. Suppose that, during stage 2 of the Stirling cycle, the gas gives up heat to the cold reservoir instead of the regenerator and, during stage 4 of the Stirling cycle, the gas absorbs heat from the hot reservoir. Assuming an ideal gas, show that the efficiency of this engine can be written as 1 ππ» π = + π ππ» β ππΆ 2 ln(π2 /π1 ) where f is the number of degrees of freedom per molecule. c. Show that the efficiency is less than that of a Carnot engine operating between the same temperatures. If πβ = 3ππΆ and π2 = 2π1 and the working substance is a monotonic ideal gas, compute the efficiency of this cycle. d. Suppose that you place the regenerator back into the system. Argue that, if it works perfectly, the efficiency of a Stirling engine is the same as that of a Carnot engine. Bonus: [6 points] Because of the importance of the Carnot theorem, you are going to perform a more formal proof of it. Let πΆ be a Carnot engine operating between the temperatures πβ and ππ (πβ > ππ ) and let π represent any other heat engine operating between the same two temperatures as shown below: Let π1 (π1β² ) refer to the energy exchanged as heat with the reservoir at πβ and let π2 (π2β² ) refer to the energy exchanged as heat with the reservoir at ππ . Consider a process consisting of πβ² cycles of π and π cycles of πΆ in reverse. a. Show that the net external work done by our system is ππ‘ππ‘ππ = πβ²|πβ²| β π|π| = πβ β ππ , where πβ = πβ²|π1 β²| β π|π1 | ππ = πβ²|π2 β²| β π|π2 | b. Use (a) and (b) and the Kelvin-Planck statement to conclude that πβ²|π2 β²| β₯ π|π2 |. Hint: Note that to as good an approximation we desire, π1 πβ² | β²| = π π1 c. Use (b) to conclude that π1 π1β² | | β₯ | β²| π2 π2
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