Objective 11D Specific heat • The amount of heat per unit mass required to raise the temperature by one degree Celsius. • The higher the specific heat, the more energy a substance can absorb. • Water’s specific heat is 4.18 J/goC Calculating energy from specific heat • As heat is added to a system, the temperature increases; increasing the energy in the system. • The formula used to calculate the energy in the system is: Q = mcΔT ENERGY MASS SPECIFIC HEAT TEMPERATURE CHANGE Examples: How many energy is needed to heat 10.0grams of water at 40oC to 65oC? If it takes 3500J of energy to raise the temperature of water from 23oC to 79oC, what is the mass of the water? Q = m c ΔT Q = m c ΔT X=(10g)(4.18J/goC)(25oC) 3500J=(X)(4.18J/goC)(56oC) X= 1045 J X= 14.95g Classroom Problem #1 36g of copper, gains 265J of energy. What was its change of temperature? Substance Aluminum Calcium Copper Gold Iron Mercury Silver Specific Heat 0.90 J/goC 0.65 J/goC 0.39 J/goC 0.13 J/goC 0.46 J/goC 0.14 J/goC 0.24 J/goC Classroom Problem #2 36.00 g of gold was heated from 20.0oC to 22.0oC. How much energy was added to the gold? Substance Aluminum Calcium Copper Gold Iron Mercury Silver Specific Heat 0.90 J/goC 0.65 J/goC 0.39 J/goC 0.13 J/goC 0.46 J/goC 0.14 J/goC 0.24 J/goC Classroom Problem #3 An 16.0-g piece of an unidentified metal was heated from 1.5oC to 19.0oC, absorbing182J of heat energy. Identify the metal. Substance Aluminum Calcium Copper Gold Iron Mercury Silver Specific Heat 0.90 J/goC 0.65 J/goC 0.39 J/goC 0.13 J/goC 0.46 J/goC 0.14 J/goC 0.24 J/goC Homework Obj.11D 1. An 18.0-g piece of an unidentified metal was heated from 21.5oC to 89.0oC. If 170J of heat energy was absorbed by the metal in the heating process, what was the specific heat of the metal? 2. If the specific heat of water is 4.18J/goC, what is the amount of heat energy required to change 15.0 grams of water at 0oC to water at 100oC? 3. 96.00 g of gold was heated from 20.0oC to 220.0oC. How much energy was added to the gold (0.13 J/goC)? 4. How much heat is needed to change the temperature of a 33-gram sample of copper from 2.7 ºC to 162.3 ºC (0.39 J/goC)? OBJECTIVE 11E CATALYSTS ALLOW A REACTION TO PROCEED WITH A LOWER ACTIVATION ENERGY. Heating curves display the temperature and state of matter for a substance. Changes in temperature require use of the specific heat formula. Q = mcΔT • How much energy is required to change 10 grams of water at 50oC to 80oC? (c = 4.18 j/goC ) Heat of fusion is the amount of energy it takes for 1 gram of a substance to change from solid to liquid or liquid to solid. E = (m) (Hf) How much energy is required to melt 10 grams of ice? (heat of fusion for water is 334 J) Heat of vaporization is the amount of energy it takes for 1 gram of a substance to change from liquid to gas or gas to liquid. E = (m) (Hv) How much energy is required to boil 10 grams of water? (heat of vaporization for water is 2257 J) Crossing the States: if both temperature and phase changes occur, use all formulas that apply. • How much energy is required to change 10 grams of ice at -50oC to steam at 180oC? Homework 1. How much energy is needed to melt 34grams of ice? (Hf = 340 J/g) 2. How much energy is needed to vaporize 57grams of water? (Hv = 2240 J/g) 3. How much energy is needed to raise the temperature of 100grams of ice from 0oC to water at 50oC? (remember: c = 4.18J/goC) 4. How much energy is needed to raise the temperature of 100grams of ice from -20oC to water vapor at 120oC? QUESTIONS YOU HAVE, ASK NOW YOU SHOULD. Objective 11DE Test : April 4-5
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