UNIVERSITY OF JOHANNESBURG APM 1B SEMESTER TEST 1 21

UNIVERSITY OF JOHANNESBURG
SEMESTER TEST 1
21 August 2014
Time: 60min
Marks: 25
APM 1B
Calculators are permitted. Angles are in radians. All physical quantities are in SI units.
QUESTION 1
[13]
The position vector of a particle is
t3 x
b + (sin t) yb
r (t) =
Determine, for t = 1;
t3 ; sin t :
(a) r; v and a.
(b) r; v and a:
(c) rb and b:
(d) r_ and r•:
(e) _ ; • and :
QUESTION 2
[12]
Given the following
a (t) =
cos t; 6t; et + 2
r (0) = (0; 0; 0)
r (1) = (3; 2; 1) ;
determine v (0) :
____________________________________________
v =
a =
dr
= r_
dt
dv
= v_
dt
v = vr rb + v b = rb
_r + r _ b
rb = (cos ; sin )
a = r•
r_
2
v = jvj
rb + r• + 2r_ _ b
b = ( sin ; cos )
r=
Z
vdt + C