2014 - 2015 FORTNIGHT TEST - 1 - e

File No.04/04/12/07/2014
VIII CLASS - IIT/N.T.S.E FOUNDATION - OLYMPIAD
ANDHRA PRADESH - TELANGANA
2014-2015 PROGRAM M E
TOTAL BITS : 45
TOTAL MARKS: 90
DATE: 14.07.2014
TIME: 45 MINUTES
FORTNIGHT TEST - 1
MATHEMATICS - NUMBER SYSTEM
1.
25102-4102 is divisible by.........
1)21
2.
2)1
55
601
8.
2)
601
55
3)
11
120
4)
120
11
2) 52
3) 48
4) 44
2)2
3)4
4)1
A prime number N, in the range 10 to 50, remains unchanged when its digits are reversed . The square of
such a number is
1)1089
7.
4)3
A number when divided by 5 leaves a remainder 3. What is the remainder when the square of the same
number is divided by 5?
1)8
6.
3)2
Find the least natural number which when divided by 6, 9, 12 and 18 leaves no remainders.
1) 36
5.
4)30
If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then
sum of the reciprocals of the numbers is equal to
1)
4.
3)29
The number in units place in 72007 is________.
1)0
3.
2)25
2)121
3)1908
A common factor of (137+117) and (1352014
+115) is-
2015
1)135+115
3)24
2)132+112
4)1890
4) 2
Three numbers which are co primes to each other are such that the product of first two is 551 and that of
the last two is 1073. The sum of the three numbers is
1) 75
9.
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11.
2) 6
3) 9
4) 0
1) 1003  2005
2) 1002  2006
3) 1004  2007
4) 1001 2006
If 12  22  32  .......  5122  m, then 22  42  6 2  ........  10242 is equal to
2) m 3
3) 4m
4) 3m
3) 40
4) 50
Number of possible divisors of 2160 is
1) 20
13.
4) 89
The value of 2007 2  20062  20052  20042  ........  22  1 
1) m 2
12.
3) 85
The least value of k so that the number 36954k is divisible by 4
1) 3
10.
2) 81
2) 30
The greatest common divisor of 136,221,391 is
1) 15
CHALLENGER
2) 16
3) 17
18) 18
1
FORTNIGHT TEST - 1
File No.04/04/12/07/2014
14.
If n = 10800, then total number of divisors of n is
1) 10
15.
VIII CLASS - IIT/N.T.S.E FOUNDATION - OLYMPIAD
2) 20
3) 40
4) 60
Find the last natural number which when divided by 6,9,12 and 18 leaves no remainders.
1) 36
2) 72
3) 12
4) 18
PHYSICS - MEASUREMENT
16.
A pressure of 106 dyne/cm2 is equivalent to
1) 105 N/m2
17.
3) 106 N/m2
4) 107 N/m2
The thimble of a screw gauge has 50 divisions for one rotation. The spindle advances 1 mm when screw is
turned through two rotations. What is the pitch of the screw?
1) 0.5 mm
18.
2) 104 N/m2
2) 0.001 cm
3) 0.077 cm
4) 0.05 m
The thimble of a screw gauge has 50 divisions for one rotation. The spindle advances 1 mm when screw is
turned through two rotations.
When the screw gauge is used to measure the diameter of wire
the reading on sleeve is found to be 0.5 mm and reading on the thimble is found 27 divisions. What is the
diameter of wire in centimeter?
1) 0.5 cm
2) 0.001 cm
3) 0.077 cm
4) 0.05 cm
19.
The pitch of the screw gauge is 1 mm there are 100 divisions on the circular scale. In measuring the
diameter of a sphere there are six divisions on the linear scale and 40th division on the circular scale
coincides with reference line then the diameter of the sphere is
1) 6.4 mm
2) 5.6 mm
3) 3.6 mm
4) 4 mm
20.
The relation between the unit ‘u’ and the magnitude ‘K’ of a physical quantity
1) u  K
21.
3) u  K 2
4) u 
1
K2
2) Force
3) Velocity
4) Mass
What are the dimensions of gravitational potential?
1) M1 L2T-2
23.
1
K
The physical quantity having the unit N Kg-1 is
1) Acceleration
22.
2) u 
2) M0L2T2
2014
- 2015
3) M0L-2T-2
4) M0 L2T-2
Least count of a vernier callipers is 0.01 cm. When the two jaws of the instrument touch each other the 5th
division of the vernier scale coincide with a main scale division and the zero of the vernier scale lies to the
left of the zero of the main scale. Furthermore while measuring the diameter of a sphere, the zero mark of
the vernier scale lies between 2.4 cm and 2.5 cm and the 6th vernier division coincides with a main scale
division
A) instrument has a positive error of 0.05 cm
B) measured reading of the instrument is 2.46 cm
C) instrument has a negative error of –0.05 cm
D) diameter of the sphere is 2.56 mm
1) A,B,C,D
24.
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3) A,B
4) B,C
In a vernier callipers 19 M.S.D coincide with 20 V.S.D. If the main scale has 20 divisions in a centimetre then
the pitch of the vernier callipers is 0.05 cm then the L.C of the vernier callipers is _________
1) 0.15 cm
25.
2) A,B,C
2) 0.25cm
3) 0.35 cm
4) 0.45cm
The pitch of the screw gauge is 1 mm there are 100 divisions on the circular scale. In measuring the
diameter of a sphere there are six divisions on the linear scale and 40th division on the circular scale
coincides with reference line then the diameter of the sphere is
1) 6.2 cm
CHALLENGER
2) 6.4 cm
3) 6.4 mm
2
4) 64 m
FORTNIGHT TEST - 1
File No.04/04/12/07/2014
VIII CLASS - IIT/N.T.S.E FOUNDATION - OLYMPIAD
CHEMISTRY - ATOMIC STRUCTURE
26.
Select the pair of isobars from the following species
1) A and B
27.
28.
2) A and C
31.
33.
3) Magnesium
4) All of these
The triad of nuclei, which is isotone, is
2) 6C12, 7N14, 9F19
In the nucleus of
4) 6C14, 7N14, 9F19
2) 10%, 90%
40
20
3) 20&, 80%
16
8
A and
18
8
A of the element.
4) 80%, 20%
Ca , there are
1) 40 prtons and 20 electrons
2) 20 protons and 40 electrons
3) 20 protons and 20 neutrons
4) 20protons and 40 neutrons
An eement M has a atomic mass 19 and atomic number 9, its ion is represented by
2) M2+
3) M-
4) M2-
The atomic mass of the lead is 208 and its atomic number is 82, the atomic mass of bismuth is 209 and its
atomic number is 83. The ratio of the neutrons/protons.
1) Is higher in lead than bismuth
2) Is lower in lead than bismuth
3) Is equal in both lead and bismuth
4) Does not depend on the above data
The number of electrons present in C6H12O6 is
2) 96
3) 108
4) 180
The number of electrons protons and neutrons in chlorine atom is
2014 - 2015
1) 18, 17, 17
35.
3) 6C14, 7N14,9F17
The average atomic mass of an element A is 16.2 u. There are two isotopes
What will be the percentage of these two isotopes in the element A?
1) 24
34.
37
36
38
B , 18
C , 18
D , 19
E
4) C and D
2) Beryllium
1) M+
32.
35
17
3) C and E
1) Helium
1) 90%, 10%
30.
A,
Which of the following elements contains only two electrons in the outermost shell?
1) 6C14, 7N15,9F17
29.
37
17
2) 17, 18, 17
3) 16, 17, 18
4) 17, 17, 18
Diameter of the nucleus is about __________ times smaller than that of the atom.
1) 108
2) 109
3) 105
4) 102
C.D.F
36.
Sum of the first ‘n odd natural numbers is______________
2) n  n  1
1) n2
37.
2) n  n  1
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n n  1
2
3) n  1
4)
n n  1
2
Sum of the first ‘n natural numbers is_______
2) n  n  1
1) n2
39.
4)
Sum of the first ‘n even natural numbers is ______________
1) n2
38.
3) n  1
3) n  1
4)
n n  1
2
Sum of the squares of the ‘n’ natural numbers is___________
1)
n n  1
2
CHALLENGER
2)
n n  1 2n  1
6
3)
n2 n  1
4
3
2
4) n(n + 1)
FORTNIGHT TEST - 1
File No.04/04/12/07/2014
40.
Newton-metre is unit for
1) Work
41.
2) 0.01
3) 0.001
4) 4
2) Negative error
3) Both the errors
4) No error.
2) -1
3) zero
4) Cannot be defined
The maximum number of electrons in M-shell are_______.
1) 2
45.
4) Pressure
The relative charge of neutron is________.
1) +1
44.
3) Force
Correction = (n - coinciding division of V.S) x L.C has
1) Positive error
43.
2) Power
Least count of vernier callipers is ________ cm
1) 0.1
42.
VIII CLASS - IIT/N.T.S.E FOUNDATION - OLYMPIAD
2) 8
3) 18
4) 32
A
In symbolic representation of an atom Zx ‘x’ represents
1) Atomic number
2) Mass number
3) Symbol of an element
4) None of these
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2014 - 2015
CHALLENGER
4
FORTNIGHT TEST - 1

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