40th World Chess Solving Championship Belgrade, 2nd-3rd August, 2016 Round 1: 3 x #2 – Time: 20 minutes NAME: ______________________________________________ COUNTRY:___________________________________________ 1) Andreas Schonholzer 3rd Prize, Freie Presse, 1969 wdwdwdwd 1.Bf2,Bh4? 1.Be5? gwdqdnHw 1.Bd6? wdwdw)wd 1.Bb8? dwhQdw0N wdwdwdkd dwdwdpGw wdw4pdw$ dwdb$wdK #2 (8 + 10) (2.Rg1#) (2.Rg1#) (2.Rg1#) (2.Rg1#) (5) 1.Bc7! (2.Rg1#) 1...S~ 1...Se6 1...Sd3 1...Qd6,Qxc7 1...f2 2.Q(x)e4# 2.Qf5# 2.Qxd7# 2.Qf5# 2.Qg2# 2) Kiril Stoyanov Het Belgisch Schaakbord (L'Echiquier Belge), 1999 wdw4wdwd dwdp0R)w BHwdwdKd dwdwdwGw wdw)kdpd gw!wdw0n wdwdNdwd dbdwdw1w #2 1...Bd6 1...d6 1...Sf4+ 1...Qxd4 2.Bb7# 2.Rxe7# 2.Rxf4# 2.Qxd4# (5) 1.Qc7! (2.Qe5#) 1...Bd6 1...d6 1...Sf4+ (9 + 10) 1...Qxd4 2.Qb7# 2.Qxe7# 2.Qxf4# 2.Sxg3# 3) Martin Anderson Original for WCSC wdwdwGKd dpdwHP!w rdwdwdpd $rdwdwiP wdwdphP$ dwdw0P)p wdwdwHwd dbdwdqdw #2 (5) 1.Sxg6! 1...Sxh5 1...Sxg6 1...Se2 1...Sg2 1...Sd3 1...Sd5 1...Se6 1...Rf6 (12 + 11) 1...Rxg6 1...Bb8! 1...Se6! 1...Sd3! 1...Bxb8! (2.gxf4#) 2.Rxh5# 2.f4# 2.Rxb5# 2.Sxh3# 2.Sxe4# 2.Qe5# 2.Be7# 2.Qh6# 2.Be7# K Q R B S P 40th World Chess Solving Championship Belgrade, 2nd-3rd August, 2016 Round 2: 3 x #3 – Time: 60 minutes K Q R B S P NAME: ______________________________________________ COUNTRY:___________________________________________ 1) Bernard Fison The English Mechanic, 1886 wdQdwdwd dpdw)wIw p)wdNdwd 4wdk)w0w qdwdwdRd dwdpdwdw Pdw)wdwG dwdwdwdw #3 (10 + 7) 1.Rc4! () 1...Rb5 1...Rc5 2.Qd7+ Kxc4 2.Sc7+ Kxc4 Kc6 Rxc7 2.Rd4+ Kxe6 2.Rxb4 & 3.Qd4# 3.Qg4# 3.Qe6# 3.Qg8# 1...Qd7 3.Qxd7# 1...Qb4 3.Rd4, Qd7, Qc4# 1...Qxc4 2.Qd7+ Ke4 3.Sxg5# 1...g4 2.Sf4+ Kxe5 3.Qe6# @ = 1.0 / 2.0 / 2.5 / 3.0 / 4.0/ 5.0 2) Virgil Nestorescu Bulletin Ouvrier des Echecs, 1952 wdwHNdwd 1.Se6! hwdwhBdw w0pdwdpd 4wdwiwdw pdwdPdwd dwdw)PdK wdP)wdwd gwdwdwdw #3 1...Sb5 1...Sf5 1...Rd5 1...c5 2.Sf4 2.f4+ 2.Sg5 2.Sf8 & Kxe4 & & 3.Sd3# 3.Sg5# 3.f4# 3.Sd7# (1) (1) (1) (1) (9 + 9) 3) Robin C. O. Matthews Bulletin Ouvrier des Echecs, 1953 rdwdndBd 1.Bf7! gr)p)wdw wdwdw0wI dwdp)R0N w$w0kdPd dwdwdwdw wdNdPdp) dwdwdnGw #3 (2.d4+ Bxd4 3.exd4#) (1) 1...Bc5 [2.Bxe8 2.Se3 1...Rxb4 2.Sxb4 1...Rxc7 2.exf6 1...fxe5 2.Bg6 (13 + 12) (3.Sxf6#) 3.Rxd4#] (1) (3.Bxd5#) Sxe3 3.Sg3# Sxc7 3.Sxf6# (3.Bxd5#) Sxc7 3.Sxf6# Se3 3.Sg3# (3.Bxd5#) Sxf6 3.Sxf6# Se3 3.Sg3# Rc5 3.Rxd4# & 3.Rf~# (1) Rb6 (1) (1) (1) 40th World Chess Solving Championship Belgrade, 2nd-3rd August, 2016 Round 3: 3 x endgame studies – Time: 100 minutes K Q R B S P NAME: ______________________________________________ COUNTRY:___________________________________________ 1) Steffen Slumstrup Nielsen Original for WCSC wdKdwdwd dwdBdwdn wdwdwdwd dwdwdwdw wdwdwdwd dwdw)Ndw wdwdwdpd dwiwdwdw + 1.Bh3 (i) 1...g1=Q 2.Nxg1 2...Ng5 3.Bg2 (ii) 3...Kd2 4.e4 4...Ke3 (or 4...Kd3) 5.e5 5...Kd4 (iii) 6.Nf3+ 6...Nxf3 7.e6 7...Nh4 (iv) 8.Be4 (v) 8...Kxe4 9.e7 9...Nf5 10.e8=Q+ 1-0 (½) (½) (½) (½) (½) (½) (½) (½) (½) (½) (i) 1. e4? Ng5 = (ii) 3.Bf5? Kd2 4.e4 Ke3 5.e5 Nf7 6.e6 Nd6+ = (iii) 5...Kf4 6.Nh3+ Nxh3 7.e6 Ng5 8.e7 Nf7 9.Kc7 1-0 (iv) 7...Ne5 8.e7 Nc4 (8...Nf7 9.Kc7 1-0) 9.Kc7 1-0 (v) 8.Kd7? Nf5 9.Bh3 Ng7,Ne3= (4 + 3) 2) Martin Minski Original for WCSC wdwdwdwd dwdwdwdw wdwdwdwd )bdwdwdw R4kdwdwd dwdwdwdw wGwdKdwd Hwdwdwdw + 1.Ra2 (i) 1...Ra4 (ii) 2. Rxa4+ (iii) 2...Kc5+ (or 2...Kd5+) (iv) 3.Rc4+ (v) 3...Kxc4 (vi) 4. Kd2 (vii) 4...Kb4 (viii) 5.Bc3+ (1) (1) (1) (1) (1) (i) (ii) 1.Rxb4+? Kxb4+ 2.Kd2 Kxa5= 1...Ba6 2.Kd2 Rb8 3.Bc3 1-0; 1...Kc5+ 2.Ke3 Kd5 3.Nc2 1-0; 1...Kd5+ 2.Kf3 Bd3 3.Bf6 1-0 (iii) 2.Ra3? Kb4+ 3.Kd2 Rxa3 4.Bxa3+ Kxa3 = (iv) 2...Bxa4 3.a6 1-0 (v) 3.Kd2? Bxa4= (vi) 3...Bxc4+ 4.Kd2/Ke3 Kb5 5.Bc3 1-0 (vii) 4.Ba3? Kd5+ 5.Kd2 Ba4 6.a6 Kc6=; 4.Nc2? Kb3+ 5.Kd2 Kxb2 =; 4.Ke3? Kb4 = (viii) 4...Ba4 5.a6 1-0 (5 + 3) 3) Daniel Keith Original for WCSC wdwdbdwd dwdwdpdw wdwdw$wd dwdwdw$K wdwdwdw0 dwdwdwdq wdwdwdwi dwdwHwdw + (4 + 5) 1. Rg4 (i) 1...Qe3 2. Nf3+ (ii) 2...Qxf3 (iii) 3. Rxf3 3...f5+ 4. Kxh4 (iv) 4...fxg4 5. Rf2+ 5...Kg1 (v) 6.Kg3 1-0. (1) (½) (½) (1) (1) (1) (i) (ii) (iii) (iv) (v) 1.Nf3+? Qxf3+ 2.Rxf3 f6+ 3.Rg6 (3.Kxh4 fxg5+ 4.Kxg5 =) 3...Bxg6+ 4.Kxg6 Kg2 =; 1.Rd5? Qc3 2.Rd2+ (2.Nf3+ Kg3 3.Rg5+ Kh3 4.Ng1+ Kh2 5.Nf3+ Kh3 =) 2...Qxd2 3.Nf3+ Kg2 4.Nxd2 h3 =; 1.Rg2+? Qxg2 2.Nxg2 Kxg2 3.Kxh4 Bd7 =; 1.Re5? Qc3 2.Rf2+ Kg1 3.Rg2+ Kf1 4.Rxe8 Qd4 =; 1.Kh6? Qe3 2.Nf3+ Kh3 3.Ng1+ Kh2= 2.Rxh4+? Kg3 3.Rg4+ Kh3 4.Rf3+ Qxf3 5.Nxf3 f5+ =; 2.Rg2+? Kh3 3.Rf3+ Qxf3+ 4.Nxf3 Kxg2 = 2...Kh3 3.Ng5+ Kh2 4.Re4 Qd3 5.Rxe8 1-0; 2...Kh1 3.Kxh4 Qf2+ 4.Rg3 Qe3 5.Rh3+ Kg2 6.Rh2+ Kf1 7.Kg3 Bb5 8.Rd6 1-0 4.Rg6? Bxg6+ 5.Kxh4 Be8 6.Rf2+ Kg1 7.Kg3 Bd7 8.Rf3 (8.Rd2 f4+ =) (8.Rf4 Be6 =) 8...Bc8 9.Rc3 f4+ = 5...Kh1 6.Kg3 Kg1 7.Re2 Bb5 8.Re1+ Bf1 9.Rd1 Kh1 10.Rxf1#
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